Integrand size = 18, antiderivative size = 82 \[ \int (d+e x)^m \left (a+b x+c x^2\right ) \, dx=\frac {\left (c d^2-b d e+a e^2\right ) (d+e x)^{1+m}}{e^3 (1+m)}-\frac {(2 c d-b e) (d+e x)^{2+m}}{e^3 (2+m)}+\frac {c (d+e x)^{3+m}}{e^3 (3+m)} \]
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Time = 0.03 (sec) , antiderivative size = 82, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.056, Rules used = {712} \[ \int (d+e x)^m \left (a+b x+c x^2\right ) \, dx=\frac {(d+e x)^{m+1} \left (a e^2-b d e+c d^2\right )}{e^3 (m+1)}-\frac {(2 c d-b e) (d+e x)^{m+2}}{e^3 (m+2)}+\frac {c (d+e x)^{m+3}}{e^3 (m+3)} \]
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Rule 712
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {\left (c d^2-b d e+a e^2\right ) (d+e x)^m}{e^2}+\frac {(-2 c d+b e) (d+e x)^{1+m}}{e^2}+\frac {c (d+e x)^{2+m}}{e^2}\right ) \, dx \\ & = \frac {\left (c d^2-b d e+a e^2\right ) (d+e x)^{1+m}}{e^3 (1+m)}-\frac {(2 c d-b e) (d+e x)^{2+m}}{e^3 (2+m)}+\frac {c (d+e x)^{3+m}}{e^3 (3+m)} \\ \end{align*}
Time = 0.13 (sec) , antiderivative size = 83, normalized size of antiderivative = 1.01 \[ \int (d+e x)^m \left (a+b x+c x^2\right ) \, dx=\frac {\left (c d^2-e (b d-a e)\right ) (d+e x)^{1+m}}{e^3 (1+m)}-\frac {(2 c d-b e) (d+e x)^{2+m}}{e^3 (2+m)}+\frac {c (d+e x)^{3+m}}{e^3 (3+m)} \]
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Time = 0.19 (sec) , antiderivative size = 135, normalized size of antiderivative = 1.65
method | result | size |
gosper | \(\frac {\left (e x +d \right )^{1+m} \left (c \,e^{2} m^{2} x^{2}+b \,e^{2} m^{2} x +3 c \,e^{2} m \,x^{2}+a \,e^{2} m^{2}+4 b \,e^{2} m x -2 c d e m x +2 c \,e^{2} x^{2}+5 a \,e^{2} m -b d e m +3 b \,e^{2} x -2 c d e x +6 a \,e^{2}-3 b d e +2 c \,d^{2}\right )}{e^{3} \left (m^{3}+6 m^{2}+11 m +6\right )}\) | \(135\) |
norman | \(\frac {c \,x^{3} {\mathrm e}^{m \ln \left (e x +d \right )}}{3+m}+\frac {d \left (a \,e^{2} m^{2}+5 a \,e^{2} m -b d e m +6 a \,e^{2}-3 b d e +2 c \,d^{2}\right ) {\mathrm e}^{m \ln \left (e x +d \right )}}{e^{3} \left (m^{3}+6 m^{2}+11 m +6\right )}+\frac {\left (b e m +c d m +3 b e \right ) x^{2} {\mathrm e}^{m \ln \left (e x +d \right )}}{e \left (m^{2}+5 m +6\right )}+\frac {\left (a \,e^{2} m^{2}+b d e \,m^{2}+5 a \,e^{2} m +3 b d e m -2 c \,d^{2} m +6 a \,e^{2}\right ) x \,{\mathrm e}^{m \ln \left (e x +d \right )}}{e^{2} \left (m^{3}+6 m^{2}+11 m +6\right )}\) | \(199\) |
risch | \(\frac {\left (c \,e^{3} m^{2} x^{3}+b \,e^{3} m^{2} x^{2}+c d \,e^{2} m^{2} x^{2}+3 c \,e^{3} m \,x^{3}+a \,e^{3} m^{2} x +b d \,e^{2} m^{2} x +4 b \,e^{3} m \,x^{2}+c d \,e^{2} m \,x^{2}+2 c \,x^{3} e^{3}+a d \,e^{2} m^{2}+5 a \,e^{3} m x +3 b d \,e^{2} m x +3 b \,e^{3} x^{2}-2 c \,d^{2} e m x +5 a d \,e^{2} m +6 e^{3} x a -b \,d^{2} e m +6 a d \,e^{2}-3 b \,d^{2} e +2 c \,d^{3}\right ) \left (e x +d \right )^{m}}{\left (2+m \right ) \left (3+m \right ) \left (1+m \right ) e^{3}}\) | \(207\) |
parallelrisch | \(\frac {x^{3} \left (e x +d \right )^{m} c \,e^{3} m^{2}+3 x^{3} \left (e x +d \right )^{m} c \,e^{3} m +x^{2} \left (e x +d \right )^{m} b \,e^{3} m^{2}+x^{2} \left (e x +d \right )^{m} c d \,e^{2} m^{2}+2 x^{3} \left (e x +d \right )^{m} c \,e^{3}+4 x^{2} \left (e x +d \right )^{m} b \,e^{3} m +x^{2} \left (e x +d \right )^{m} c d \,e^{2} m +x \left (e x +d \right )^{m} a \,e^{3} m^{2}+x \left (e x +d \right )^{m} b d \,e^{2} m^{2}+3 x^{2} \left (e x +d \right )^{m} b \,e^{3}+5 x \left (e x +d \right )^{m} a \,e^{3} m +3 x \left (e x +d \right )^{m} b d \,e^{2} m -2 x \left (e x +d \right )^{m} c \,d^{2} e m +\left (e x +d \right )^{m} a d \,e^{2} m^{2}+6 x \left (e x +d \right )^{m} a \,e^{3}+5 \left (e x +d \right )^{m} a d \,e^{2} m -\left (e x +d \right )^{m} b \,d^{2} e m +6 \left (e x +d \right )^{m} a d \,e^{2}-3 \left (e x +d \right )^{m} b \,d^{2} e +2 \left (e x +d \right )^{m} c \,d^{3}}{e^{3} \left (m^{3}+6 m^{2}+11 m +6\right )}\) | \(340\) |
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Leaf count of result is larger than twice the leaf count of optimal. 201 vs. \(2 (82) = 164\).
Time = 0.29 (sec) , antiderivative size = 201, normalized size of antiderivative = 2.45 \[ \int (d+e x)^m \left (a+b x+c x^2\right ) \, dx=\frac {{\left (a d e^{2} m^{2} + 2 \, c d^{3} - 3 \, b d^{2} e + 6 \, a d e^{2} + {\left (c e^{3} m^{2} + 3 \, c e^{3} m + 2 \, c e^{3}\right )} x^{3} + {\left (3 \, b e^{3} + {\left (c d e^{2} + b e^{3}\right )} m^{2} + {\left (c d e^{2} + 4 \, b e^{3}\right )} m\right )} x^{2} - {\left (b d^{2} e - 5 \, a d e^{2}\right )} m + {\left (6 \, a e^{3} + {\left (b d e^{2} + a e^{3}\right )} m^{2} - {\left (2 \, c d^{2} e - 3 \, b d e^{2} - 5 \, a e^{3}\right )} m\right )} x\right )} {\left (e x + d\right )}^{m}}{e^{3} m^{3} + 6 \, e^{3} m^{2} + 11 \, e^{3} m + 6 \, e^{3}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 1416 vs. \(2 (70) = 140\).
Time = 0.61 (sec) , antiderivative size = 1416, normalized size of antiderivative = 17.27 \[ \int (d+e x)^m \left (a+b x+c x^2\right ) \, dx=\text {Too large to display} \]
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Time = 0.20 (sec) , antiderivative size = 132, normalized size of antiderivative = 1.61 \[ \int (d+e x)^m \left (a+b x+c x^2\right ) \, dx=\frac {{\left (e^{2} {\left (m + 1\right )} x^{2} + d e m x - d^{2}\right )} {\left (e x + d\right )}^{m} b}{{\left (m^{2} + 3 \, m + 2\right )} e^{2}} + \frac {{\left (e x + d\right )}^{m + 1} a}{e {\left (m + 1\right )}} + \frac {{\left ({\left (m^{2} + 3 \, m + 2\right )} e^{3} x^{3} + {\left (m^{2} + m\right )} d e^{2} x^{2} - 2 \, d^{2} e m x + 2 \, d^{3}\right )} {\left (e x + d\right )}^{m} c}{{\left (m^{3} + 6 \, m^{2} + 11 \, m + 6\right )} e^{3}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 350 vs. \(2 (82) = 164\).
Time = 0.26 (sec) , antiderivative size = 350, normalized size of antiderivative = 4.27 \[ \int (d+e x)^m \left (a+b x+c x^2\right ) \, dx=\frac {{\left (e x + d\right )}^{m} c e^{3} m^{2} x^{3} + {\left (e x + d\right )}^{m} c d e^{2} m^{2} x^{2} + {\left (e x + d\right )}^{m} b e^{3} m^{2} x^{2} + 3 \, {\left (e x + d\right )}^{m} c e^{3} m x^{3} + {\left (e x + d\right )}^{m} b d e^{2} m^{2} x + {\left (e x + d\right )}^{m} a e^{3} m^{2} x + {\left (e x + d\right )}^{m} c d e^{2} m x^{2} + 4 \, {\left (e x + d\right )}^{m} b e^{3} m x^{2} + 2 \, {\left (e x + d\right )}^{m} c e^{3} x^{3} + {\left (e x + d\right )}^{m} a d e^{2} m^{2} - 2 \, {\left (e x + d\right )}^{m} c d^{2} e m x + 3 \, {\left (e x + d\right )}^{m} b d e^{2} m x + 5 \, {\left (e x + d\right )}^{m} a e^{3} m x + 3 \, {\left (e x + d\right )}^{m} b e^{3} x^{2} - {\left (e x + d\right )}^{m} b d^{2} e m + 5 \, {\left (e x + d\right )}^{m} a d e^{2} m + 6 \, {\left (e x + d\right )}^{m} a e^{3} x + 2 \, {\left (e x + d\right )}^{m} c d^{3} - 3 \, {\left (e x + d\right )}^{m} b d^{2} e + 6 \, {\left (e x + d\right )}^{m} a d e^{2}}{e^{3} m^{3} + 6 \, e^{3} m^{2} + 11 \, e^{3} m + 6 \, e^{3}} \]
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Time = 10.07 (sec) , antiderivative size = 201, normalized size of antiderivative = 2.45 \[ \int (d+e x)^m \left (a+b x+c x^2\right ) \, dx={\left (d+e\,x\right )}^m\,\left (\frac {c\,x^3\,\left (m^2+3\,m+2\right )}{m^3+6\,m^2+11\,m+6}+\frac {d\,\left (2\,c\,d^2-b\,d\,e\,m-3\,b\,d\,e+a\,e^2\,m^2+5\,a\,e^2\,m+6\,a\,e^2\right )}{e^3\,\left (m^3+6\,m^2+11\,m+6\right )}+\frac {x\,\left (-2\,c\,d^2\,e\,m+b\,d\,e^2\,m^2+3\,b\,d\,e^2\,m+a\,e^3\,m^2+5\,a\,e^3\,m+6\,a\,e^3\right )}{e^3\,\left (m^3+6\,m^2+11\,m+6\right )}+\frac {x^2\,\left (m+1\right )\,\left (3\,b\,e+b\,e\,m+c\,d\,m\right )}{e\,\left (m^3+6\,m^2+11\,m+6\right )}\right ) \]
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